Two pipes p and Q fill a water tank. Each pipe fills the tank with water at a constant rate. Pipe P fills the tank with 20 gallons of water in 4 minutes. The equation in equals 6t shows the number of gallons of water n with which pipe you fills the tank in t minutes. Which pipe fills the tank with more water each minute and by how much

Pipe Q

Step-by-step explanation:

Two pipes p and Q fill a water tank. Each pipe fills the tank with water at a constant rate. Pipe P fills the tank with 20 gallons of water in 4 minutes. The equation in equals n = 6t shows the number of gallons of water n with which pipe Q fills the tank in t minutes. Which pipe fills the tank with more water each minute and by how much

Solution:

Pipe P fills the tank with 20 gallons of water in 4 minutes. If n represent the number of gallons of water that fills the tank in t minutes, then for pipe P:

n = 20 gallons / 4 minutes *t

n = 5t

Also, the number of gallons of water that fills the tank in t minutes for pipe Q is given by:

n = 6t

Since the rate at which pipe Q fills the tank (i.e. 6t) is greater than the rate at which pie P fills the tank (i.e. 5t), hence Pipe P  fills the tank with more water each minute by 6 gallons while pipe P fills by 5 gallons each minute.

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."

step-by-step explanation: