Can someone help me in this it’s due today

Q1. (a) (i) p = -9, q = 11

Q3. (a) Line 1: x = 0.5

           Line 2: x = -2

Q3. (b) (i) (ii) For both lines, they will be perpendicular to the x-axis and they will pass their respective x-coordinates of 1 and -2 1/2.

Step-by-step explanation:

Q1. (a) (i) 5(-5) - 3p = 2

-25 - 3p = 2

3p = -25 - 2

p = -27/3

p = -9

5(7) - 3q = 2

35 - 3q = 2

3q = 35 - 2

3q = 33

q = 11

Q3. (a) Since all points on Line 1 have x-coordinates of 0.5, we can conclude that the equation is x = 0.5. Same goes for Line 2, of which all points have x-coordinates of -2 instead, making the equation x = -2.

Hope this helped!

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