Q2(a) Draw a square EFGH of side 4cm.
(a)Draw the locus of points at most 2cm from the
boundary of the square.[2]

(b) Draw the locus of point Q on the same side of EG as H,
so that 90o [2]

(d) Let x0 be the bearing of the point P from G. By
measuring the minimum and maximum possible
bearing, fill in the following statement: [2]
< xo <

i believe the correct answer is b.

a) y = -3x +2

b) y = 1/2x -6

these 2 can be combined into one equation.

-3x +2 = .5x -6

8 = 3.5x

x = 8 / 3.5 = 2.2857142857

y = -3 * (8 / 3.5) +2

y = (-24 / 3.5) + 2

y = -4.8571428571

step-by-step explanation:

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step-by-step explanation:

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