Solve pls CORRECTLY!

\huge \bf \: GivenGiven

The sides of a triangle are in ratio = 1:2:3

\huge \bf \: To \: findTofind

The sides

\huge \bf \: SolutionSolution

Let us assume that the sides to be x

As we know that sum of all sides of triangle is 180

Therefore,

\sf \: 1x + 2x + 3x = 1801x+2x+3x=180

Now,

Finding value of x

\sf \: 6x = 1806x=180

\sf \: x \: = \dfrac{180}{6}x=

6

180

\sf \: x \: = 30x=30

Therefore sides will be

\tt \: x = 30x=30

\tt \: 2x = 2(30) = 602x=2(30)=60

\tt \: 3x = 3(30) = 903x=3(30)=90

Let's verify

\rm30 + 60 + 90 = 18030+60+90=180

\rm \: 180 = 180180=180

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answer: two angles are called supplementary if they add up to 180°. example: the two angles (140° and 40°) are supplementary because they add up to 180°.

step-by-step explanation: