WILL GIVE BRAINLIEST!! Roslyn has ten boxes. Six of the boxes contain pencils, three of the boxes contain pens, and two of the boxes contain both pens and pencils. How many boxes contain neither pens nor pencils?

1 of the boxes have neither in them

Step-by-step explanation:

From the original 20 boxes, since 3 have neither pens nor pencils, let's put those boxes aside. Now we have only 17 boxes.

Of these 17 boxes, some many have only pens, some may have only pencils, and some may have both pens and pencils.

We know that 13 of them have pencils and since every box that we now have has either pens or pencils or both, the 4 boxes that don't have pencils must have pens.

But, since 9 boxes have pens (subtracting 4 boxes from 9 boxes, giving us 5 boxes), 5 of these boxes must be boxes that also have pencils.

If we look inside all the boxes, we will find that 8 boxes have only pencils, 5 boxes have both pens and pencils, and 4 boxes have only pens. (And 3 that have neither pens nor pencils.)

since we know that the two functions are equal, f (x) = g

(x), therefore when we equate the two equations the result should be similar to

3x = x – 4:

a. f(x) = 3x, g(x) = x – 4

equating the two functions:

3x = x – 4             (correct)

so we now got our answer (a)