Jan and Kim own numbers of marbles that are in the ratio 5:6
Jan gains 2 more marbles and the ratio is
now 7:8
how many marbles do each own initially?

honestly i did it wrong most likely so just read the comment above

5:6 + 7:8 = 12:14

Jan will have 12 marbles

Kim will have 14 marbles

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

-7/8

step-by-step explanation:

instead of subtracting you add the -6/8 and -1/8