Find all possible values of b such that 4x^2+bx+3 can be factored?

13,7,8 but if there’s an answer choice go with 7,8

Step-by-step explanation: Assuming b is an integer, we first look at factors of 4, being 1 and 4 or 2 and 2. The factors of 3 are 1 and 3 only. So the factorisation possibilities are (x+3)(4x+1), (4x+3)(x+1) and (2x+1)(2x+3).

Expanding these we get: 4x²+13x+3, 4x²+7x+3 and 4x²+8x+3, giving values of b=13, 7 and 8

it should be a and d. lmk if i'm wrong xd

1.3

step-by-step explanation:

3x2=6   9x+6

bring down the 6 on both sides

6+6=12

12= 9x

divide by 9

12/9 =

1.3 =x