F(x)= 2x^2+4x+10
G(x)= 3x-11
H(x)= 3x^3+x^2-21

The value of H(F(G(2)))

Step-by-step explanation:

H(F(6-11))

H(F(-5))

H(F(50-20+10))

H(40))

3×(40^3)+40^2-21

=193579

courtesan no naked yes

hope this ^_^

do you see a nakes

the image of (6, 9) under a dilation is (4, 6). the scale factor is