Some marbles in a bag are red and the rest are blue. If one red marble is removed, then one-seventh of the remaining marbles are red. If two blue marbles are removed
instead of one red, then one-fifth of the remaining marbles are red. How many
marbles were in the bag original

Pls give EXPLANATION

22

Step-by-step explanation:

Let r be red and b be blue

1/7(r-1+b)=r-1

1/5(r+b-2)=r

r-1+b=7(r-1)

r+b-2=5r

r-1+b=7r-7

1=7r-7-5r

8=2r

r=4

1/5(4+b-2)=4

2+b=20

b=18

18+4=22

step-by-step explanation:

in the absence of parentheses, i will have to make some assumptions:   i interpret your (3x+5/y^6)(4y^3/5)​ to mean:

3x + 5     4y^(3/5)       (3x + 5)(4)

* =

    y^6             1               y^(6-3/5)

if this is not what you expected, repost your question using parentheses to indicate whether you meant

4y^3

    or   4y^(3/5)

    5

answer: i think the answer is etheir c or d but i don't know which one but have a good day!

step-by-step explanation: