Linda shoots an arrow at a target in an archery competition. The arc of the arrow can be modeled by the equation below. Note: x is the horizontal distance (in meters) from Linda and y is the height (in meters) of the arrow. How far from Linda does the arrow hit the ground?

37.8 metre

Step-by-step explanation:

CHECK THE COMPLETE QUESTION BELOW;

Linda shoots an arrow at a target in an archery competition. The arc of the arrow can be modeled by the equation y= -0.02x to the power of 2 + 0.65+4 where x is the horizontal distance (in meters) from Linda and y is the height (in meters) of the arrow. How far from Linda does the arrow hit the ground? Round to the nearest tenth.

From the question, we are told that the equation that modelled the arc is

y=-0.02x²+0.65x+4

From the question, "x" in the equation=

the horizontal distance (in meters

While "y" in the equation = the height (in meters) of the arrow.

We can find the value of x and y by equating to zero(since arrow hits the ground when its height (y) is zero) then solve the quadratic equation using quadratic formula

y=-0.02x²+0.65x+4=0

We have, x=37.79 or -5.29

The negative x= -5.29 can be described as been at the back of Linda,

But the distance is of positive value, therefore, the arrow hit the ground at 37.8 metre from Linda after Rounded to the nearest tenth.

answer is c

step-by-step explanation:

81/12=324/x

x=48

the answer is b.

surface area: 169π

volume: 366π

i got it down.