16w^2+18w+1

I need the you to show work

w=(-9+√65)/16 or ((-9-√65)16

Step-by-step explanation:

This quadratic cannot be factorises using the method of factorization so for this example I choose to use the general quadratic formula;

x=(-b±√b²-4ac)/2a

By comparing 16w²+18w+1 with ax²+bx+c, a=16,b=18,c=1 and we plug them into the formula and simplify

w={-18±√(18)²-4(16×1)}/2(16)

w={-18±√324-64}/32

w={-18±√260}/32

w=(-18±2√65)/32

w=(-9+√65)/16 or ((-9-√65)16

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)

1/3

step-by-step explanation:

to find this, you can divide 12 by 4 which is 3 or you can multiply 4 until you reach 12 (4x3=12). both should give you 3, meaning theres three times less bananas than there are oranges.