2(w-1)+8=6(2w-4) pls help

w = 3

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDASEquality Properties

Step-by-step explanation:

Step 1: Define equation

2(w - 1) + 8 = 6(2w - 4)

Step 2: Solve for w

Distribute:                                   2w - 2 + 8 = 12w - 24Combine like terms:                   2w + 6 = 12w - 24Subtract 2w on both sides:       6 = 10w - 24Add 24 on both sides:               30 = 10wDivide 10 on both sides:            3 = wRewrite:                                       w = 3

Step 3: Check

Plug in w into the original equation to verify it is a solution.

Substitute in w:                    2(3 - 1) + 8 = 6(2(3) - 4)Multiply:                                2(3 - 1) + 8 = 6(6 - 4)Subtract:                               2(2) + 8 = 6(2)Multiply:                                4 + 8 = 12Add:                                      12 = 12

Here we see that 12 does indeed equal 12.

∴ w = 3 is a solution of the equation.

The operation is suck a c@ck? !