Solve by factoring: 2sinxcosx=sinx in [0,2π)

2sin(x)cos(x) = sin(x)

2sin(x)cos(x) - sin(x) = 0

sin(x)(2cos(x) - 1) = 0

sin(x) = 0

x = 0, pi, 2pi

2cos(x) - 1 = 0

cos(x) = 1/2

x = pi/3,  5π/pi

x = 0, pi/3, pi, 5 pi/3,  2 pi

hope it helps

i really dont know

step-by-step explanation:

step-by-step explanation:

here's what happens:

1) the graph of f   = x^2 is shifted 2 units to the right.

2) the resulting graph is reflected in the x-axis, so that the parabola now opens down.

3) this final result is transformed up by 5 units.