Rearrange y= 2(x-a)/x to make x the subject

x = -2a/(y - 2).

Step-by-step explanation:

y= 2(x-a)/x

Cross multiply:

xy = 2(x - a)

xy = 2x - 2a

xy - 2x = -2a

x(y - 2) = -2a

x = -2a/(y - 2).

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

35 is an outlier

step-by-step explanation: