1. which two points lie on a line with slope 2/3?
a. (2, 0) and (3,0)
b. (3, –4) and (1, 2)
c. (0, 0) and (2, 3)
d. (–3, 2) and (0, 4)
2. what is the slope of the line that passes through the given points?
(6, –1) and (–3, –1)
a. undefined
b. 0
c. – 2/3
d. – 3/2
4. write the equation in slope-intercept form. what are the slope and y-intercept?
3/4x + 4/5y = 4
a. y = 15/16x + 5; slope: 5; y-intcerpt: 15/16
b. y = 15/16x – 5; slope: 15/16 : y-intercept: –5
c. y = –15/16x – 5; slope: –15/16; y-intercept: –5
d. y = –15/16x + 5; slope: –15/16; y-intercept: 5

1.) If you graph the points you will find the (D) (-3,2) and (0,4) has a slope of 2/3

2.) If you graph this also you will find that it is a straight line, this means that the slope is 0.

3.) Slope-intercept form would be y=mx+b.

So you would subtract 3/4x from each side to get y by itself. Then you will have 4/5y=-3/4x+4. You need to get rid of the 4/5 to get y by itself so you need to multiply each side by 5/4.

(5/4)(-3/4)=-15/16. Don't forget the 4, so (4/1)(5/4). Make the denominator the same, (16,4)(5/4)=80/16 which simplifies down to 5. Now you have y=-15/16x+5. Now you know what the slope is and the y-intercept.

The slope will be -15/16 and the y-intercept will be 5.

So, 1) D 2) B 3)D

ab will be equal to