Will give brainliest!! How many ways are there to divide a red bracelet, a yellow bracelet, a green bracelet, and a black bracelet among 4 people if each person must receive exactly 1 of the bracelets?

Any of the 4 could receive the red bracelet
After thisany of the remaining 3 people without a bracelet could receive the yellow bracelet
After thiseither of the remaining 2 people without a bracelet could receive the green bracelet
And, by default, the remianing person without a bracelet will get the black bracelet

4x3x2x1= 24

So the answer is 24

Please mark me as brainliest I really need it :)

Ais c multiple rthvjjbv