Let x denote the number of missing pieces in a randomly selected 500-piece puzzle from a local thrift shop. The variable x has the following probability distribution: x01234
P(X)0.330.440.20.020.01
Calculate and interpret σx. (4 points)

0.33; if we were to select many puzzles randomly, we would expect about 0.33 to have all their pieces
0.83; if we were to select many puzzles randomly, the number of missing puzzle pieces would typically vary about 0.83 from the mean
0.94; if we were to select many puzzles randomly, we would expect about 0.94, on average, to be missing pieces
0.2; if we were to select many puzzles randomly, the number of missing puzzle pieces would typically vary about 0.2 from the mean
1.58; if we were to select many puzzles randomly, we would expect about 1.58, on average, to be missing pieces