Task 2 Equation

a

b

Discriminant

Nature of the

Roots

x2 - 6x-27 = 0

x2 - 25 - 0

x2 + 10x + 25 - 0

2x2 - 5x + 3 = 0

HELP PLEASEE

Step-by-step explanation:

For a quadratic expression ax²+bx + c = 0

The discriminant D = b²-4ac

Given the following quadratic equation;

x^2 - 6x-27 = 0

a = 1, b = -6, c = -27

D = (-6)²-4(-27)

D = 36+108

D = 144

Hence the discriminant is 144

For the roots;

x = -b±√D/2a

x = 6±√144/2

x = 6±12/2

x = 18/2 and -6/2

x = 9 and -3

For the expression x2 - 25 = 0

a = 1, b = 0 and c = -25

D = (0)²-4(-25)

D = 100

Hence the discriminant is 100

For the roots;

x = 0±√100/2

x = ±10/2

x = ±5

x =-5 and 5

Given the following quadratic equation;

x^2 +10x+25 = 0

a = 1, b = 10, c = 25

D = (10)²-4(25)

D = 100-100

D = 0

Hence the discriminant is 0

For the roots

x = -10±√0/2

x = -10/2

x = -5

Given the following quadratic equation;

2x^2 - 5x+3 = 0

a = 2, b = -5, c = 3

D = (-5)²-4(2)(3)

D = 25-24

D = 1

Hence the discriminant is 1

For the roots;

x = 5±√1/2(2)

x = 5±1/4

x = 5+1/4 and 5-1/4

x = 6/4 and 4/4

x = 3/2 and 1

x = 18/2 and -6/2

x = 9 and -3

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.