A farmer has 96 apples to sell at the farmers market. She wants to bag the apples before going. How many ways can the farmer bag the apples so that: each bag has at least 4 apples each bag has no more than 10 apples all bags have the same number of apples

Answer and explanation:

Farmer's number of apples = 96 apples

Given that Farmer needs to bag the apples so that there are at least 4 apples in each bag(not less than 4 apples in each bag) and not more than 10 apples in each bag

And also all apples in each bag are equal

We need to find the numbers between 4 and 10(including 4 and 10) that can divide 96 without a remainder

4 can divide 96= 24

5 cannot divide 96 without remainder

6 can divide 96 =16

7 cannot divide 96 without remainder

8 can divide 96=12

9 cannot divide 96 without remainder

10 cannot divide 96 without remainder

From the above we see that the factors of 96 = 4, 6, 8 between 4 and 10

4 apples = 24 bags

6 apples = 16 bags

8 apples = 12 bags

Therefore, there can be 3 possible ways of having equal number of apples in each bag between 4 and 10 apples

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length

idkidkdidkdkdidkx

step-by-step explanation:

nndncnd cnn

snddnd