Victoria kicked a soccer ball laying on the ground. It was in the air for 6 seconds before it hit the ground. While the soccer ball was in the air it reached a height of approximately 25 feet. Assuming that the soccer ball’s height (in feet) is a function of time (in seconds), what is the maximum in the context of this problem? Group of answer choices

(6, 25)

(3, 12.5)

(3, 25)

(20, 3)

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3, 25

Step-by-step explanation:

The seconds should be the x-axis and the height is y axis. Also thinking about how a kicked ball makes an arch, the max is 25, and the mid point between 0 and 6 is 3.

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116

my guess would be b and d, but i didn’t actually get out the pen and paper. lol