A country's population in 1993 was 204 million. In 2000 it was 208 million. Estimate
the population in 2015 using the exponential
growth formula. Round your answer to the
nearest million. HURRY PLEASEE

Step-by-step explanation:To solve the exponential growth application question we proceed as follows;

suppose the time, t between 1993 to 2000 is such that in 1993, t=0 and in 2000, t=7.

Note theta the population is in millions;

The exponential formula is given by:

f(t)=ae^(kt)

where;

f(t) =current value

a=initial value

k=constant of proportionality

t=time

substituting the values we have in our formula we get:

132=127e^(7k)

132/127=e^(7k)

introducing the natural logs we get:

ln (132/127)=7k

k=[ln(132/127)]/7

k=0.0055

Thus our formula will be:

f(t)=127e^(0.0055t)

The population in 2008 will be:

f(t)=127e^(15*0.0055)=127e^(0.0825)=137.922

Thus the population in 2008 is appropriately 138 million.

answer: the distance

step-by-step explanation:

to calculate the distance d of a line segment with endpoints (x1, y1) and (x2, y2) use the formula d (x2 x1)2 (y2 y1)2. to calculate the midpoint of a line segment with endpoints (x1, y1) and (x2, y2) use the formula

2 over 5 and 4 over 15

don’t know last one sorry

step-by-step explanation: