Find the minimum value of C=4x+3
Subject to the following constraints :
x ≥ 0
y ≥ 0
2x+3y ≥ 6
3x - 2y ≤ 9
x+5y ≤ 20

C=4x+3y Constraints: x is greater than or equal to 0 2x + 3y is greater than or equal to 6 3x - 2y is less than or equal to 9 x + 5y is less than or equal to 20

81 seats

step-by-step explanation:

if you multiply 0.65 times 125 then you get 81.5 seats. well since you can't have half of a seat you have to round down and get 81 seats in the no children zones. that leave 44 seats outside of the no children zone.