Write the equation of the line in slope intercept form that passes through the point (4,5) and is perpendicular to the graph of y=2x-3

y = -½x + 7

Step-by-step explanation:

Perpendicular lines have the product of their gradients equal to -1

For this to be true, since the first gradient is 2, the second gradient must be -½

So the first part is

y = -½x + c

We substitute our point to get c

5 = -½(4) + c

7 = c

Our line is

y = -½x + 7

FYI slope-intercept form is y = mx + c