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Mathematics, 03.12.2020 22:50 Elazjah

. An object is launched straight up into the air. It is launched from a height of H feet off the ground. Its height H, in feet, at t seconds is given by the
equation H = -8t^2 + 40t + 18. Find all times t that the object is at a height
of 50 feet off the ground.

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