Mathematics, 03.12.2020 19:00 rileyeddins1010
Below is the proof that ED CB. The proof is divided into two parts, where the title of each part indicates its main purpose
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Mathematics, 21.06.2019 16:40
The graph of which equation includes the points (0, 10) and (10, 11)? y = 10x + 11 y = x + 10 y= 1/10x + 10 y = 1/10x + 11
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Mathematics, 21.06.2019 21:30
Questions 9-10. use the table of educational expenditures to answer the questions. k-12 education expenditures population indiana $9.97 billion 6.6 million illinois $28.54 billion 12.9 million kentucky $6.58 billion 4.4 million michigan $16.85 billion 9.9 million ohio $20.23 billion 11.6million 9. if the amount of k-12 education expenses in indiana were proportional to those in ohio, what would have been the expected value of k-12 expenditures in indiana? (give the answer in billions rounded to the nearest hundredth) 10. use the value of k-12 education expenditures in michigan as a proportion of the population in michigan to estimate what the value of k-12 education expenses would be in illinois. a) find the expected value of k-12 expenditures in illinois if illinois were proportional to michigan. (give the answer in billions rounded to the nearest hundredth) b) how does this compare to the actual value for k-12 expenditures in illinois? (lower, higher, same? )
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Mathematics, 22.06.2019 04:30
Consider the linear model for a two-stage nested design with b nested in a as given below. yijk=\small \mu + \small \taui + \small \betaj(i) + \small \varepsilon(ij)k , for i=1,; j= ; k=1, assumption: \small \varepsilon(ij)k ~ iid n (0, \small \sigma2) ; \small \taui ~ iid n(0, \small \sigmat2 ); \tiny \sum_{j=1}^{b} \small \betaj(i) =0; \small \varepsilon(ij)k and \small \taui are independent. using only the given information, derive the least square estimator of \small \betaj(i) using the appropriate constraints (sum to zero constraints) and derive e(msb(a) ).
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Mathematics, 22.06.2019 04:30
Me with these questions , i don’t understand scientific notation!
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Below is the proof that ED CB. The proof is divided into two parts, where the title of each part ind...
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