Evaluate cube root of 7 multiplied by the square root of 7 over sixth root of 7 to the power of 5 . (5 points) 7−1
1
7
7 to the power of 5 over 3

Answer to your question: a. the fundamental theorem of algebra tells you that the equation will have two complex roots since the degree of the polynomial is 2. the roots are ​ x=1±i7√2 .number of roots=degree of polynomialhere, degree of polynomial is 2 so number of roots will be 2.hope it *_*

Your answer is b hope this