Tamara is creating a model of a rectangle. She has ab26 inches of yellow ribbon to use for the border of the rectangle. She wants the length,/, to be 3 inches greater than the width, w. Which system of equations could tamara use to find the dimnesions of a rectangle that uses all of the ribbon

Step-by-step explanation:

Step one:

given data

we are told that the border/perimeter of the yellow ribbon is 26in

let the  width be x

W=x

and the lenght

L=x+3

Step two:

Required

The expression for the perimeter to find the dimensions of the yellow ribbon given the above condition.

we know that the perimeter of a rectangle is given as

P=2L+2W

26=2(x+3)+2xThis is the expression required

26=2x+6+2x

26=4x+6

26-6=4x

20=4x

divide both sides by 4

x=20/4

x=5in

The width is 5in

The length is

L=x+3

L=5+3

L=8in

$5.41

step-by-step explanation:

$20 - $14.51 = $5.49.

simplifying

5(x + -6) = 2(x + 3)

reorder the terms:

5(-6 + x) = 2(x + 3)

(-6 * 5 + x * 5) = 2(x + 3)

(-30 + 5x) = 2(x + 3)

reorder the terms:

-30 + 5x = 2(3 + x)

-30 + 5x = (3 * 2 + x * 2)

-30 + 5x = (6 + 2x)

solving

-30 + 5x = 6 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-30 + 5x + -2x = 6 + 2x + -2x

combine like terms: 5x + -2x = 3x

-30 + 3x = 6 + 2x + -2x

combine like terms: 2x + -2x = 0

-30 + 3x = 6 + 0

-30 + 3x = 6

add '30' to each side of the equation.

-30 + 30 + 3x = 6 + 30

combine like terms: -30 + 30 = 0

0 + 3x = 6 + 30

3x = 6 + 30

combine like terms: 6 + 30 = 36

3x = 36

divide each side by '3'.

x = 12

simplifying

x = 12

this should .