A medical school claims that more than 28% of its students plan to go into general practice. It is found that among a random sample of 130 of the schools students 32% of them plan to go into general practice. Find the p- value for a test of the schools claim

0.1548

Step-by-step explanation:

The P value can be calculated from the value of the test statistic :

H0 : p ≤ 0.28

H1 : p > 0.28

Zstat :

(p - p0) / √((p0(1-p0))/n)

p = 0.32 ; p0 = 0.28 ; n = 130

(0.32 - 0.28) / √((0.28(1 - 0.28))/130)

Zstat = 1.0157490

Zstat = 1.016

Using a 0.05 significance ;

The P value obtained using the p value from z statistic calculator is 0.154815

c > -10.55

step-by-step explanation:

answer: idk wbu

step-by-step explanation: umm..