What are the zero(s) of the function f(x) = the quantity of 5 x squared minus 25 x, all over x? x = 5 x = 0 and x = 5

(5x^2-25x)/x
simplify
((x)(5)(x-5))/x=5(x-5)=5x-25=f(x)
(just fyi, that x we cancled is a hole)
set to zero
5x-25=0
5x=25
divide 5
x=5

zeroe is at x=5
or (5,0)

x=5 is answer

1. isolate the variable, in this case, d. subtract 35.5 on both sides of the equation.2. 52 subtracted by 35.5 is 16.53. therefore your answer would be d= 16.5this is the basics of pre algebra, isolating variable through adding, subtracting, multiplying, and dividing, if you have any other questions to ask just comment!