The table shows the gallons of fuel remaining after a car travels a certain distance in miles. The change in fuel remaining from one row to the next in the table is gallon(s).

The change in distance from one row to the next in the table is mile(s).

The slope of the line that runs through the points given in the table is .

The slope indicates a .

-0.04

1

-0.04

Loss of 0.04 gallons of fuel for every 1 mile

Step-by-step explanation:

I just took it

The table shows the gallons of fuel remaining after a car travels a certain distance in miles.

The change in fuel remaining from one row to the next in the table is  

✔ –0.04

gallon(s).

The change in distance from one row to the next in the table is  

✔ 1

mile(s).

The slope of the line that runs through the points given in the table is  

✔ –0.04

.

The slope indicates a  

✔ loss of 0.04 gallons of fuel for every 1 mile

Step-by-step explanation:

✔✔✔✔✔✔✔✔

i think it's eleven too, don't woosh me here, but according to the "experts" it's 2.

the proof starts from the peano postulates, which define the natural

numbers n. n is the smallest set satisfying these postulates:

  p1.   1 is in n.

  p2.   if x is in n, then its "successor" x' is in n.

  p3.   there is no x such that x' = 1.

  p4.   if x isn't 1, then there is a y in n such that y' = x.

  p5.   if s is a subset of n, 1 is in s, and the implication

      (x in s => x' in s) holds, then s = n.

then you have to define addition recursively:

  def: let a and b be in n. if b = 1, then define a + b = a'

      (using p1 and p2). if b isn't 1, then let c' = b, with c in n

      (using p4), and define a + b = (a + c)'.

then you have to define 2:

  def:   2 = 1'

2 is in n by p1, p2, and the definition of 2.

theorem:   1 + 1 = 2

proof: use the first part of the definition of + with a = b = 1.

      then 1 + 1 = 1' = 2   q.e.d.

note: there is an alternate formulation of the peano postulates which

replaces 1 with 0 in p1, p3, p4, and p5. then you have to change the

definition of addition to this:

  def: let a and b be in n. if b = 0, then define a + b = a.

      if b isn't 0, then let c' = b, with c in n, and define

      a + b = (a + c)'.

you also have to define 1 = 0', and 2 = 1'. then the proof of the

theorem above is a little different:

proof: use the second part of the definition of + first:

      1 + 1 = (1 + 0)'

      now use the first part of the definition of + on the sum in

      parentheses:   1 + 1 = (1)' = 1' = 2   q.e.d.

vertical asymptote .

horizontal asymptote .

step-by-step explanation:

given function is .

vertical asymptote is given by setting

denominator =0

when degree of numerator and denominator are same then divide first term of numerator by first term of denominator to get horizontal asymptote.