What are the zeros of the quadratic function f(x) = 6x2 – 24x + 1? x = –2 + sqrt(1/2) or x = –2 – sqrt(1/2)

x = 2 + sqrt(1/2) or x = 2 – sqrt(1/2)

x = –2 + sqrt(23/6) or x = –2 – sqrt(23/6)

x = 2 + sqrt(23/6) or x = 2 – sqrt(23/6)

i dont know if you cant find a way its best to actually add all of them start from 105 tho

step-by-step explanation:

a

step-by-step explanation:

the denominator cannot be the same as one of the factors.

8 denominator times 2 denominator = 16

and 7 numerator time 11 = 77

77/16= 77/16 ( they cannot be further simplified)

step-by-step explanation:

why? because i noticed a pattern. 60 120. those numbers without the zero, make the 6 times tables leaving your answer to be b since 6 times 4 is 24 and adding a zero making it 240.