(ABCD) = (A'B'C'D'). If A is (6, −8), A' is (−2, 4), and B is (4, −6), what are the coordinates of B'?

(6, 6)

In this problem the point is moved over 2 up and 2 to the right form A to A'

since the airplane is moving with constant speed then the distance travelled can be calculated by x=u*t

in km/h would be:

x=640*3.5=2.240 km

in m/s would be:

u=640 km/h= 640.000 m/h =640.000/ 3600 m/s =177.8 m/s

t= 3.5 h= 3.5 * 3600 s=12.600 s

then x=u*t= 177.8*12.600= 2.240.280 m

22

step-by-step explanation: