Find a formula for the function f(x) such that f′(x)=sin(x) and f(2)=5.

f(x) = -cos(x) + 4.584

Step-by-step explanation:

we know that f'(x) = sin(x)

if we integrate that, we get:

f(x) = -cos(x) + C

Where C is a constant of integration.

And we also want that:

f(2) = 5

with that relationship we can find the value of C.

f(2) = 5 =  -cos(2) + C

(The calculation is done in radians)

        5 = -(-0.416) + C

       5 - 0.416 = C = 4.584

Then the function is:

f(x) = -cos(x) + 4.584

idk the answer but just put a

step-by-step explanation: