A simple off bacteria is debating according to the half life model. If the simple begins with 800 bacteria, and after 18 minutes there is 240 bacteria, after how many minutes will there be 40 remaining

After 43 minutes, the bacteria will be 40 remainings.

Step-by-step explanation:

Given that:

Initial population of bacteria = 800

After time (t) = 18 mins

A = 240

Using the model:

By applying natural log on both sides, we get:

In(0,3) = 18k (In e)

- 1.20397 = 18 k * (1)

18 k = -1.20397

k =  -1.20397/ 18

k = - 0.06688

k ≅ -0.07

After time (t), the bacteria population (A) = 40

Now;

In (0.05) = -0.07t * In (e)

- 2.9957 = - 0.07t

t = - 2.9957/ -0.07

t = 42.795

t ≅ 43 minutes

Thus, after 43 minutes, the bacteria will be 40 remainings.

step-by-step explanation:

just plug in each number for x and see which ones work and don't

d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;