What is the solution to the system of inequalities graphed below? Y=-x+3 y=x-3 A. (3,0)
B. (-3,0)
C.(0,-3)
D. (0,3)

Use continuity to evaluate the limit. lim x→16 20 + x 20 + x step 1 consider the intervals for which the numerator and the denominator are continuous. the numerator 20 + x is continuous on the interval the denominator 20 + x is continuous and nonzero on the interval

What is the value of r of the geometric series?

Can someone check if i did this correct. it’s number 4 if you’re wondering.