1.) Banyak suku dari bentuk aljabar 2a + 3b - 4c + 6 adalah... a. 2
b. 5
c. 4
d. 3

2.) Hasil dari -6ab(4ab² + 2a²b - 3ab) adalah..
a. -24a²b² + 2a²b - 3ab
b. -24a²b³ + 2a²b - 3ab
c. -24a²b³ + 12a³b² - 18a²b²
d. -24a²b³ - 12a³b² + 18a²b²

3.) Banyak himpunan bagian dari A = {bilangan prima kurang dari 15} adalah
a. 4
b. 16
c. 32
d. 64

explanation:

previous steps have made pa≅ pb ≅ st ≅ su. setting the compass width to ab allows you to make tu the same length. then δstu ≅ δpab by the sss congruence postulate, and ∠p ≅ ∠s by the reason cpctc.

t= 1/3.

hope this .

step-by-step explanation:

3 4 7 12 19

+1 +3 +5 +6

i would guess 26 because this isnt a sequential pattern or its to short to know