Which system of equations has no solution? 5 x + 5 y = 10 and 2 x + 2 y = 4

3 x minus 6 y = 4 and negative 4 x + 8 y = 7

6 x + 2 y = 6 and 7 x + 3 y = 9

3 x minus 4 y = 16 and 2 x + 3 y = 5

Question #2

Two linear equations are represented by using the tables below.

A 2-column table with 4 rows is titled Equation A. Column 1 is labeled x with entries negative 5, negative 2, 0, 1. Column 2 is labeled y with entries negative 4, negative 1, 1, 2.
A 2-column table with 4 rows is titled Equation B. Column 1 is labeled x with entries negative 6, negative 3, 3, 6. Column 2 is labeled y with entries negative 4, negative 2, 2, 4.

The data points for equation A are plotted on the coordinate plane below and are connected by using a straight line.

On a coordinate plane, a line goes through points (negative 5, negative 4), (negative 2, negative 1), (0, 1), (1, 2).

What is the solution to the system of equations?
(–6, –4)
(–5, –4)
(–3, –2)
(0, 1)

is (-3,-2)

Step-by-step explanation:

because you are graphing them on a chart find

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step-by-step explanation:

let's call the solutions x₁ = (5 - 2√7)/3 and x₂ = (5 + 2√7)/3

then the equation is (x-x₁)(x-x₂) = 0

if you fill that in you get a lot of numbers which you can recognize as ax²+bx+c=0.

step-by-step explanation:

you can see that a=1 (there is just an x²)

b = (-5 -2√7 + 2√7 - 5)/3 = -10/3

c = -2√7)/3 ) * (-5+2√7)/3) = -1/3

so your answer is 3x^2 – 10x – 1 = 0