Whats the equation for a line thats perpendicular to 6x-2y=8 when it passes through (6,-5) ( i hope i wrote that right sorry)

Equation of required line is:

Step-by-step explanation:

We need to find equation for a line that's perpendicular to when it passes through (6,-5)

We will use the slope-intercept form: where m is slope and b is y-intercept.

Finding Slope m:

When two lines are perpendicular there slopes are

Finding slope of given equation first:

Writing in slope-intercept form:

Comparing it with slope intercept form: , m= 3

So, slope of given equation is 3

Now, the slope of required equation will be

So, Slope m=-1/3

Finding y-intercept

Using slope m=-1/3 and point (6,-5) we can find y-intercept

So, y-intercept is b=-3

Now, finding the equation of required line having Slope m=-1/3 and y-intercept b= -3

Writing in standard form:

So, equation of required line is:

12

step-by-step explanation:

12 + 5 = 17

12x2=24

24-7=17