A ball is shot from the ground straight up into the air with initial velocity of 48 ft/sec. Assuming that the air resistance can be ignored, how high does it go? Hint: The acceleration due to gravity is 32 ft per second squared.
Given f''(x) = 4x + 2 and f'( - 1) = 3 and f( - 1) = – 6.
Find f'(x) = and find f(4)
Given f''(x) - 9 sin(3x) and f'(0) = – 1 and f(0) = - 6. 7T
Find f