Part A )a painter leans a ladder up against a building. The base of the ladder is placed 7 feet from the building to reach a height of 24 feet. How long is the ladder Part B) The painter uses the same ladder from part A, but now needs to reach a height of 19 feet. How far away does the base of the ladder need to be placed from the building?

Part A). 25 feet

Part B). 16.25 feet

Step-by-step explanation:

Part A). By applying Pythagoras theorem in ΔABC,

            AC² = AB² + BC²

            AC² = (24)² + 7²

            AC² = 576 + 49

            AC = √625

                  = 25 feet

Part B). By applying Pythagoras theorem in ΔABC,

            AC² = AB² + BC²

           (25)² = (19)² + x²

           625 = 361 + x²

           x² = 625 - 361

           x = √264

           x = 16.25 feet

answer: i'm not going to give you the answer, but some hints to work it out.

step-by-step explanation: so, if there is a straight line that means that the line angle is 180°. so we subtract the 2 angle measures provided, (15 and 38) from 180. so the answer is 180 - (38 + 15). (you have to solve the equation)