The length of a rectangle is 3 cm more than twice its width. find the largest possible width if the perimeter is at most 66cm

If you let the width be x, then the length will be 2x + 3. The perimeter P is twice the width plus twice the length, i.e., P = 2*x + 2*(2x + 3) = 2x + 4x + 6 = 6x + 6. So if the perimeter is 66 cm then 66 = 6x + 6 ---> 6x = 60 ---> x = 10 cm., and so if the perimeter is at most 66 cm., the width can be at most 10 cm..

Let the length be L

Let the width be W.

L is 3cm more than twice its width.

L = 2W + 3

P = 2*(L + W)

P = 2*(2W + 3 + W)

P = 2*(3W + 3)

P = 6W + 6

Since Perimeter is at most 66, so P is less than or equal to 66.

P ≤ 66

6W + 6 ≤ 66

6W ≤ 66 - 6

6W ≤ 60

W ≤ 60/6

W ≤ 10

So the largest possible width is 10cm.

Largest possible width is 10cm.

I hope this helped.