Fuseina has ¢40000 to invest. She decides to put part of the money in an account paying 4% interest and the reminder into stocks paying 6% interest . Her financial advisor tells her that the total annual income from these investments should be¢2040. How much should she invest at each rate?

The amounts invested in the account = ¢ 18000

and the amount invested in the stock = ¢40000-¢18000= ¢22000.

Step-by-step explanation:

Given that the account paying 4% interest and the stocks paying 6% interest.

Assuming she put ¢ x in the account, so

Income (interest) from the account = 4% of x = ¢ 0.04x...(i)

She has a total of ¢ 40000 to invest, so the remaining amount = ¢(40000-x).

As she put the remaining amount into stock, so

Income (interest) from the stock=6% of (40000-x)=¢(2400-0.06x)...(ii)

As total income from the investment is ¢ 2040, so on adding both the incomes from equations (i) and (ii), we have

So, the amount invested in the account = ¢ 18000

and the amount invested in the stock = ¢40000-¢18000= ¢22000.

answer: we have from thales theorem that because the 2 triangles are similar, jm/jk=jn/jl. we have that jn=x, jl=x+24 and that jm=7 and jk=28. substituting, we get:

x/(x+24)=7/28.

hence, x/(x+24)=1/4. this leads to 4x=x+24, 3x=24, x=8. we have solved for x=jn and this is equal to 8.

step-by-step explanation: