Drag each number to the correct location on the equations. Each number can be used more than once, but not all numbers will be used. Roy and Elisa are buying tickets for the annual school concert. Roy buys 6 adult tickets and 2 child tickets for a total of $66. Elisa buys 5 adult tickets and 4 child tickets for a total of $62. Determine the system of equations that can be used to find the cost of one adult ticket, a, and the cost of one child ticket, c. 66 62 5 2 8 128 4 6

a=$10

c=$3

Step-by-step explanation:

Step one:

given data

let adults tickets be a

and child tickets be c

so

Roy's purchase

6a+2c=661

Elisa's purchase

5a+4c=622

Hence,  the system of equations

6a+2c=661

5a+4c=622

solving simultaneously

6a+2c=661 x2

5a+4c=622 x1

  12a+4c=132

 -5a+4c=62

   7a=70

divide both sides by 7

a=$10

put  a=70 in 1

6(10)+2c=661

60+2c=66

2c=66-60

2c=6

c=$3

the answer is somewhere there guys it really . there im just not gonna answer

step-by-step explanation:

but i'm guessing ur first option tho