How do you solve the y-intercept? And did I solve slope correctly?

Step-by-step explanation:

y intercept is when the line crosses the y axis

so in this case its (0,0)

the slope is close but its actually 3/2 or 1.5

the equation is y=1.5x

what you did wrong here was misinterpet the slope formula

you did x/y instead of y/x

place r′ so that qr′ is parallel to the tangent.

now we get that ∠r′py=∠pr′q, where y is on the tangent, on the opposite side of p from x.

also, because of the symmetry, ∠r′py=∠qpx.

finally, note that no matter where we place r, as long as it's on the correct arc, we have ∠prq=∠pr′q.

stringing all these equalities together, we end up with ∠prq=∠qpx.

this picture will show how its going to look like.

hope this by jack monhen