Adult male heights are normally distributed with a mean of 70 inches and a standard deviation of 3 inches. The average basketball player is 79 inches tall. Approximately what percent of the adult male population is taller than the average basketball player? (2 points) a
0.135%

b
0.875%

c
49.875%

d
99.875%

This answer did not come from me but credit to ApusApus
We have been given that adult male heights are normally distributed with a mean of 70 inches and a standard deviation of 3 inches. The average basketball player is 79 inches tall.
We need to find the area of normal curve above the raw score 79.
First of all let us find the z-score corresponding to our given raw score.
, where,
,
,
,
.
Upon substituting our given values in z-score formula we will get,

Now we will find the P(z>3) using formula:

Using normal distribution table we will get,

Let us convert our answer into percentage by multiplying 0.00135 by 100.

Therefore, approximately 0.135% of the adult male population is taller than the average basketball player and option A is the correct choice.

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All you have to do is multiply