AB←→ intersects PQ←→ at point M; Point C is on AB←→ ;

Point R is on PQ←→ ;

△CMR is a right triangle.

Which statement describes the relationship between AB←→ and PQ←→ ?

A.

AB←→ and PQ←→ are skew

B.

AB←→ and PQ←→ are collinear

C.

AB←→⊥PQ←→

D.

AB←→∥PQ←→

(C).  AB←→⊥PQ←→

Step-by-step explanation:

This is the only suitable answer to produce a triangle △CMR which is a right triangle.

When we will draw Line AB And PQ which they are intersecting And to produce a right triangle by taking two random points ( C on AB and  P on PQ).

Then AB and PQ must be Perpendicular to each other, only then a triangle CMR will be right angled at M.

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47

2/3

step-by-step explanation:

the slope of a line is equal to the rise/run. in this case the line rises 2 units for every +3 units it moves