EXPENSES: Camille has no more than $50.00 to spend each week for lunch and bus fare. Lunch costs $3.00 each day, and bus fare is $1.75 each ride. Write an inequality for this situation. Can Camille buy lunch 7 times and ride the bus 14 times in one week

Inequality:

She can afford to buy the lunch and bus rides

Step-by-step explanation:

Given

daily

daily

Solving (a) The inequality

Let bus ride be represented with B and Lunch be represented with L

If 1 bus ride costs $1.75, then

B bus ride would cost $1.75 * B

If 1 lunch costs $3.00, then

L lunch would cost $3.00 * L

Total Spending is then the sum of the above expression i.e.

$3.00 * L + $1.75 * B

The question says Camille can not spend more than $50.00.

This is represented by less than or equal to.

So, the expression is:

Solving (b): Can she afford 7 lunch and 14 bus ride?

To do this, we simply substitute 7 for L and 14 for B

The above inequality is true.

Hence, she can afford to buy the lunch and bus rides

question 1 is 8, question 2 is 9, question 3 is 24

step-by-step explanation:

now, the numbers they give you at the top are the key. from there, you just have to plug and chug! let's try 1, 2, and 3!

key: a=3, b=5, c=6

1. a+5

remember, a=3, so we plug that in to get 3+5=8

2. 15-c

c=6, so we plug that in to get 15-6=9

3. 4b

b=6, so we plug it in to get 4*6=24

time to try the rest on your own! if you put the answers below in a comment, i'll check them for you!