Help me with this question pleaseee

Step-by-step explanation:

Remark

If the horizontal lines are parallel, then 2x +  20 = 3x - 10

Equation

2x + 20 = 3x - 10

Add 10 to both sides

2x + 20 + 10 = 3x

Subtract 2x from both sides

30 = x

2x + 20 = 2*30 + 20 = 80

x = 30 and both the angles are 80°

In the given figure,

∠(2x + 20) = ∠(3x - 10)             [corresponding angles]

20 = x - 10                                [subtracting 2x from both sides]

x = 30                                      [adding 10 on both sides]

Value of the angles:

the questions required us to find the measure of a certain ∠XAE, but since we cannot see an ∠XAE in the image provided, we will find the measure of both the angles     [let ∠(2x + 20) = ∠1     and     ∠(3x-10) = ∠2]

Measure of ∠1:

We are given that the magnitude of ∠1 is:

∠1 = 2x + 20

since x = 30

∠1 = 2(30) + 20                             [replacing the value of x]

∠1 = 80°

Measure of ∠2:

We are given that the magnitude of ∠2 is:

∠2 = 3x - 10

since x = 30

∠2 = 3(30) - 10                              [replacing the value of x]

∠2 = 80°

5x + 5

step-by-step explanation:

you should always add the diagrams and graphs we cannot see. this particular question is kind of borderline because we can make a graph for you.

(f + g)x = -x^2 +3x + 5 + x^2 + 2x

(f + g)x = 5x + 5

the graph of z = 5x + 5 is shown below. always use desmos when in doubt.