On a subway route, station c is located at the midpoint between stations a and d. station b is located at the midpoint between stations a and c. if the distance between stations a and d is 2.4 kilometers, what is the distance between stations b and d?

1.8 Km

Step-by-step explanation:

Given

C is mid station between A & D

So Distance between A and C is equal to distance between D and C

And distance between A & D is 2.4 km

Thus AC=1.2 Km

Also B is the mid-station of A & C

Thus AB =BC

therefore AB=BC=0.6 Km

so distance between B & D is 1.2+0.6 =1.8 Km

B is distance of AD

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

the infinity sign

step-by-step explanation: