4 ≤ y + 2 ≤ -3(y-2)+24

The solution graph is also attached.

Step-by-step explanation:

Given

as

so

solving the intervals

as

subtract 2 from both sides

also

subtract 2 from both sides

Add 3y to both sides

Divide both sides by 4

so combining the intervals

Merge overlapping intervals

Therefore,

The solution graph is also attached.

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step-by-step explanation:

step-by-step explanation:

assume that you have 3 different side lengths.   apply the pythagorean theorem here:   square each of the two shortest sides; call them a and b, so that their squares are a² and b².   also square the longest side, calling the result c².

now, if a² + b² = c² is true, the triangle is a right triangle; otherwise it is not a right triangle.